Galileo writes that for angles of projection of a projectile at angles (450+$$ θ$$) and (450$$ $$-$$ θ$$) , the horizontal ranges described by the projectile are in the ratio of (if$$ θ ≤ $$450$$ $$)

Question

Infinity Learn · Accepted Answer

R $$=$$ $$u2/g$$ $$sin2$$α $$=$$ $$u2/g$$ $$sin$$ $$($$π $$-$$ $$2$$α$$)$$ $$=$$ $$u2/g$$ $$sin2($$π$$/2$$ $$-$$ α$$)$$⇒ R $$=$$ $$u2/g$$ $$sin2$$α $$=$$ $$u2/g$$ $$sin$$ $$2$$ßWhere ß $$=$$ π$$/2$$  $$-$$ α  $$=$$ Another angle of projection which produces the same range.Here α $$+$$ ß $$=$$ π$$/2If$$  α $$=(450$$ $$+$$θ$$)$$ , ß must be equal to (450$$ $$-$$ θ$$).: Option $$-$$ (3) is right.

Galileo writes that for angles of projection of a projectile at angles (45⁰+ θ) and (45⁰ - θ) , the horizontal ranges described by the projectile are in the ratio of (if θ ≤ 45⁰ )

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

Galileo writes that for angles of projection of a projectile at angles (450+ θ) and (450 - θ) , the horizontal ranges described by the projectile are in the ratio of (if θ ≤ 450 )

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

Galileo writes that for angles of projection of a projectile at angles (45⁰+ θ) and (45⁰ - θ) , the horizontal ranges described by the projectile are in the ratio of (if θ ≤ 45⁰ )