Galileo writes that for angles of projection of a projectile at angles (450+ θ) and (450 - θ) , the horizontal ranges described by the projectile are in the ratio of (if θ ≤ 450 )

R = u2/g sin2α = u2/g sin (π - 2α) = u2/g sin2(π/2 - α)⇒ R = u2/g sin2α = u2/g sin 2ßWhere ß = π/2  - α  = Another angle of projection which produces the same range.Here α + ß = π/2If  α =(450 +θ) , ß must be equal to (450 - θ).: Option - (3) is right.