Questions
A galvanometer has a current range of 15 m A and a voltage range of 750 mV. To convert this galvanometer into ammeter of range 25 amp the shunt required is
detailed solution
Correct option is B
Given that the galvanometer has a current range of 15 mA i.e., ig = maximum current measured =15×10−3 amp. Maximum voltage measured= 750 x 10-3 V∴Galvanometer resistanceG=750×10−315×10−3=50ΩNow S=ii−igG=15×10−3×5025−15×10−3≃0⋅03ΩSimilar Questions
A tangent galvanometer has a coil with 50 turns and radius equal to 4 cm. A current of 0.1 amp is passing through it. The plane of the coil is set parallel to the earth's magnetic meridian. If the value of the earth's horizontal component of the magnetic field is 7x 10-5 Tesla and weber/amp' x metre, then the deflection in the galvanometer needle will be
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