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A galvanometer has a current range of 15 m A and a voltage range of 750 mV. To convert this galvanometer into ammeter of range 25 amp the shunt required is

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0.3 Ω

0.03 Ω

0.01 Ω

cannot be estimated as resistance of galvanometer is not given

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detailed solution

Correct option is B

Given that the galvanometer has a current range of 15 mA i.e., ig = maximum current measured =15×10−3 amp. Maximum voltage measured= 750 x 10-3 V∴Galvanometer resistanceG=750×10−315×10−3=50ΩNow S=ii−igG=15×10−3×5025−15×10−3≃0⋅03Ω

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