Questions
A galvanometer has a resistance of and a maximum of 0.01 A current can be passed through it. In order to change it into an ammeter of range 10 A, the shunt resistance required is
detailed solution
Correct option is D
ig=i SG+S ⇒ 0.01=10 S25+S⇒ 1000 S=25+S ⇒ S=25999 ΩTalk to our academic expert!
Similar Questions
A moving coil galvanometer converted into an ammeter reads up to 0.03 A by connecting a shunt of resistance 4r across it and ammeter reads up to 0.06 A, when a shunt of resistance r is used. What is the maximum current which can be sent through this galvanometer if no shunt is used?
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