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A galvanometer has a resistance of 25  Ω and a maximum of 0.01 A current can be passed through it. In order to change it into an arnmeter of range 10 A, the shunt resistance required is

a
5/999  Ω
b
10/999  Ω
c
20/999  Ω
d
25/999  Ω

detailed solution

Correct option is D

ig=i SG+S  ⇒  0.01 = 10  S25+S⇒  1000 S =  25+S  ⇒  25999 Ω

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