First slide

CIrcuit questions

Question

A galvanometer has a resistance of $3663 Ω$ . A shunt S is connected across it such that 1/34 of the total current passes through the galvanometer. The value of the shunt is

Moderate

A

$3663 Ω$
B

$111 Ω$
C

$107 .7 Ω$
D

$3555 .3 Ω$

Solution

$\begin{array}{l} i_{g} \times r_{g} = (i - i_{g}) \times S \\ \Rightarrow S = \frac{i_{g}}{(34 i_{g} - i_{g})} \times 3663 Ω = 111 Ω \end{array}$

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