Download the app

Questions  

A galvanometer, having a resistance of 50Ω, gives a full sale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross-section 2.97x 10-6 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (specific resistance of the wire = 5 x 10-7Ω m)

a
8
b
6
c
3
d
1.5

detailed solution

Correct option is C

Here i=G+SSigor 5=50+RR×0⋅05∴ R=(50/99)Now, R=ρlA  or  l=RAρ∴ l=(50/99)×2.97×10−65×10−7=3m

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A galvanometer of 50 ohm resistance has 25 divisions 'A current of 4x 10-4 ampere gives a deflection of one division. To convert this galvanometer into a volt metre having a range of 25 volts, it should be connected with a resistance of


phone icon
whats app icon