Questions
A galvanometer, having a resistance of 50 gives a full scale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross-section 2.97x 10-2 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (specific resistance of wire = 5 x 10-7 m)
detailed solution
Correct option is C
We know that i−igS=igG∴ i=(G+S)SigTherefore 5=50+RR×0⋅05or R=2⋅54⋅95Further R=ρlA or l=ARρor l=2⋅97×10−6×(2⋅5)5×10−7×4⋅95=3mSimilar Questions
The resistance of a moving coil galvanometer is 10 and gives a full scale deflection for a current 5 mA The series resistance required to convert it into a voltmeter to read maximum 100 volt is
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