Questions
A galvanometer of 50 ohm resistance has 25 divisions. A current of ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of
detailed solution
Correct option is D
Full deflection current, ig = 25 × 4 × 10−4=100 × 10−4 AR=Vig −G = 25100 × 10−4 −50=2450 Ω in seriesTalk to our academic expert!
Similar Questions
A voltmeter has an internal resistance of 1000 Ω and gives full scale deflection when 2 V is applied across the terminals. Now a resistance of 4000 Ω is connected in series with it. Then it gives full scale deflection with
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