First slide

Moving coil Galvanometer

Question

A galvanometer of 50 ohm resistance has 25 divisions. A current of $4 \times 10^{- 4}$ ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of

Moderate

A

$2500 Ω as a shunt$
B

$2450 Ω as a shunt$
C

$2550 Ω in series$
D

$2450 Ω in series$

Solution

Full deflection current, $i_{g} = 25 \times 4 \times 10^{- 4}$
$\begin{array}{l} = 100 \times 10^{- 4} A \\ R = \frac{V}{i_{g}} - G = \frac{25}{100 \times 10^{- 4}} - 50 = 2450 Ω in series \end{array}$

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