A galvanometer of 50 ohm resistance has 25 divisions. A current of 4 × 10-4 ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of

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2500 Ω as a shunt

2450 Ω as a shunt

2550 Ω in series

2450 Ω in series

answer is D.

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Detailed Solution

Full deflection current, ig = 25 × 4 × 10−4=100 × 10−4 AR=Vig −G = 25100 × 10−4 −50=2450 Ω in series

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