Questions
A galvanometer of 50 ohm resistance has 25 divisions 'A current of 4x 10-4 ampere gives a deflection of one division. To convert this galvanometer into a volt metre having a range of 25 volts, it should be connected with a resistance of
detailed solution
Correct option is D
Given that, G = 50 Ωig=25×4×10−4amp=10−2ampTo convert the galvanometer into voltmeter, high resistance should be connected in series with it. The value of high resistance fi is given byR=Vig−G=2510−2−50=2500−50=2450ΩTalk to our academic expert!
Similar Questions
A galvanometer, having a resistance of 50, gives a full sale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross-section 2.97x 10-6 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (specific resistance of the wire = 5 x 10-7 m)
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