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Q.

A galvanometer of 50 ohm resistance has 25 divisions 'A current of 4x 10-4 ampere gives a deflection of one division. To convert this galvanometer into a volt metre having a range of 25 volts, it should be connected with a resistance of

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a

2500 Ω as a shunt

b

245  Ω as a shunt

c

2550 Ω in series

d

2450 Ω in series

answer is D.

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Detailed Solution

Given that, G = 50 Ωig=25×4×10−4amp=10−2ampTo convert the galvanometer into voltmeter, high resistance should be connected in series with it. The value of high resistance fi is given byR=Vig−G=2510−2−50=2500−50=2450Ω
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