First slide

Moving coil Galvanometer

Question

A galvanometer of resistance 200 $Ω$ gives a full scale deflection for a current of10^-3 A. To convert it into an ammeter capable of measuring up to 1 A, what resistance should be connected in parallel with it ?

Easy

A

2 x 10^-6 $Ω$
B

2 x10^-3 $Ω$
C

2 x10^-1 $Ω$
D

2 $Ω$

Solution

We know that
$S = (\frac{i_{g}}{i - i_{g}}) G$
Substituting the given values, we get
$S = \frac{10^{- 6}}{(1 - 10^{- 6})} \times 200$
or $S = 0 \cdot 2 Ω$

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