Questions
A galvanometer of resistance 200 gives a full scale deflection for a current of10-3 A. To convert it into an ammeter capable of measuring up to 1 A, what resistance should be connected in parallel with it ?
detailed solution
Correct option is C
We know that S=igi−igGSubstituting the given values, we getS=10−61−10−6×200or S=0⋅2ΩTalk to our academic expert!
Similar Questions
A galvanometer, having a resistance of 50, gives a full sale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross-section 2.97x 10-6 cm2 that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is (specific resistance of the wire = 5 x 10-7 m)
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