A galvanometer of resistance 200 Ω gives a full scale deflection for a current of10-3 A. To convert it into an ammeter capable of measuring up to 1 A, what resistance should be connected in parallel with it ?

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2 x 10-6 Ω

2 x10-3Ω

2 x10-1Ω

2 Ω

answer is C.

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Detailed Solution

We know that S=igi−igGSubstituting the given values, we getS=10−61−10−6×200or S=0⋅2Ω

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