A galvanometer of resistance 30 ohm is converted into an ammeter of range 2.8 A by connecting a shunt resistance 12 ohm to the galvanometer. What can be the range of ammeter if a resistance 6 ohm is connected in parallel to the shunt 12 ohm?

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3.6 A

4.8 A

5.2 A

6.8 A

answer is D.

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Detailed Solution

IIg=S+GS⇒I1I2=S1+GS2+G×S2S1S1=12 Ω and S2=12×612+6=4Ω2.8I2=4234×412I2=6.8 A

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