In a galvanometer, there is deflection of 5 divisions per μA current. The resistance of galvanometers is 40 ohm. If shunt of 2 ohm is connected and if there are 50 divisions all over the scale of galvanometer, then the maximum current that can be measured by it is

s=Gn-1 where G is the galvanometer resistance   and n is the amplification factor2=40n-1; n=21     before     connecting     shunt     it     measures     a     current     of        50  ×  15=  10     μA     now     it     measures     21  ×  10=  210     μA=  0  .  21     mA