In a galvanometer, there is deflection of $$5$$ divisions per μA current. The resistance of galvanometers is $$40$$ ohm. If shunt of $$2$$ ohm is connected and if there are $$50$$ divisions all over the scale of galvanometer, then the maximum current that can be measured by it is

Question

In a galvanometer, there is deflection of $$5$$ divisions per μA current. The resistance of galvanometers is $$40$$ ohm. If shunt of $$2$$ ohm is connected and if there are $$50$$ divisions all over the scale of galvanometer, then the maximum current that can be measured by it is

Infinity Learn · Accepted Answer

$$s=Gn-1$$ where G is the galvanometer resistance   and n is the amplification $$factor2=40n-1$$; $$n=21$$     before     connecting     shunt     it     measures     a     current     of        $$50$$  ×  $$15=$$  $$10$$     μA     now     it     measures     $$21$$  ×  $$10=$$  $$210$$     μ$$A=$$  $$0$$  .  $$21$$     mA

In a galvanometer, there is deflection of 5 divisions per $μ$ A current. The resistance of galvanometers is 40 ohm. If shunt of 2 ohm is connected and if there are 50 divisions all over the scale of galvanometer, then the maximum current that can be measured by it is

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In a galvanometer, there is deflection of 5 divisions per μA current. The resistance of galvanometers is 40 ohm. If shunt of 2 ohm is connected and if there are 50 divisions all over the scale of galvanometer, then the maximum current that can be measured by it is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

In a galvanometer, there is deflection of 5 divisions per $μ$ A current. The resistance of galvanometers is 40 ohm. If shunt of 2 ohm is connected and if there are 50 divisions all over the scale of galvanometer, then the maximum current that can be measured by it is