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Q.

A galvanometer whose resistance is 120  Ω gives fuIl scale deflection with a curren of 0.05 A so that it can read a maximum current of 10 A. A shunt resistance is added in parallel with it. The resistance of the ammeter so formed is

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a

0.06  Ω

b

0.006  Ω

c

0.6  Ω

d

6  Ω

answer is C.

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Detailed Solution

Resistance of shunted ammeter =GSG+SAlso iig =1  +  GS  ⇒GSG+S = ig.Gi⇒GSG+S =  0.05 ×  12010 = 0.6 Ω
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