First slide

Moving coil Galvanometer

Question

A galvanometer whose resistance is $120 Ω$ gives fuIl scale deflection with a curren of 0.05 A so that it can read a maximum current of 10 A. A shunt resistance is added in parallel with it. The resistance of the ammeter so formed is

Easy

A

$0.06 Ω$
B

$0.006 Ω$
C

$0.6 Ω$
D

$6 Ω$

Solution

Resistance of shunted ammeter $= \frac{GS}{G + S}$
$\begin{array}{l} Also \frac{i}{i_{g}} = 1 + \frac{G}{S} \Rightarrow \frac{GS}{G + S} = \frac{i_{g} . G}{i} \\ \Rightarrow \frac{GS}{G + S} = \frac{0 .05 \times 120}{10} = 0 .6 Ω \end{array}$

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