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A galvanometer whose resistance is 120  Ω gives fuIl scale deflection with a curren of 0.05 A so that it can read a maximum current of 10 A. A shunt resistance is added in parallel with it. The resistance of the ammeter so formed is

a
0.06  Ω
b
0.006  Ω
c
0.6  Ω
d
6  Ω

detailed solution

Correct option is C

Resistance of shunted ammeter =GSG+SAlso iig =1  +  GS  ⇒GSG+S = ig.Gi⇒GSG+S =  0.05 ×  12010 = 0.6 Ω

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