First slide
Electrical measuring instruments
Question

Galvanometer with 50 divisions on the scale has a resistance of  25Ω. A current of 2×10-4 A gives a deflection of one scale division. The additional series resistance required to convert it into a voltmeter reading up to 25 V is ……….. ohm.

Easy
Solution

Maximum deflection current  ig=50  ×2×10-4=10-2 A G = 25 Ω  Now, V = igR+G 25=102R + 25 R = 2475 Ω   

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