First slide

Heat given

Question

For a gas, the difference between the two specific heats is 4150J Kg^-1 K^-1 and the ratio of specific heats is 1.4. What is the specific heat of the gas at constant volume in J Kg^-1 K^-1 ?

Moderate

A

8475
B

5186
C

1660
D

10375

Solution

$\gamma = 1.4;R = 4150Jk{g^{ - 1}}{k^{ - 1}}$
${C_V} = \frac{R}{{\gamma - 1}} = \frac{{4150}}{{1.4 - 1}} = \frac{{41500}}{4}$
$= 10375Jk{g^{ - 1}}{k^{ - 1}}$

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