A gas is enclosed in a cylinder with a movable frictionless piston. Its initial thermodynamic state at pressure Pi=105Pa and volume Vi=10−3m3 changes to final state at Pf=132×105Pa & Vf=8×10−3m3 in an adiabatic quasi-static process, such that P3V5=constant. Consider another thermodynamic process that brings the system from the same initial state to the same final state in two steps: an isobaric expansion at Pi followed by an isochoric (isovolumetric) process at volume Vf. The amount of heat supplied to the system in the two-step process is approximately
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a
112 J
b
294 J
c
588 J
d
813 J
answer is C.
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Detailed Solution
Case 1 : PV53=constant⇒γ=53 , Monoatomic gasProcess is adibatic.W=PfVf−PiVi1−γ=132×105×8×10−3−105×10−31−53=112.5J⇒△U=−W=−112.5JCase 2 : Wisobaric=PiVf−Vi=1058×10−3−10−3=700JWisochoric=0⇒Wnet=700JFirst law of thermodynamics,Q=△U+Wnet=−112.5+700=587.5J=588 J nearly