A gas is expanded from volume V0 to 2V0 under three different processes. Process 1 is isobaric process, process 2 is isothermal process and process 3 is adiabatic. Let ΔU1,ΔU2 and ΔU3 be the change in internal energy of the gas in these three processes. Then
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a
ΔU1>ΔU2>ΔU3
b
ΔU1<ΔU2<ΔU3
c
ΔU2>ΔU1>ΔU3
d
ΔU2<ΔU3<ΔU1
answer is A.
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Detailed Solution
Change in temperature in process 1 will be greater as it is isobaric and in process 3 will be least as it is adiabatic expansion in which work will be done using internal energy .