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A gas expands adiabatically at constant pressure such that its temperature $T \propto \frac{1}{\sqrt{V}}$ , the value of $\frac{C_{p}}{C_{v}}$ of gas is

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detailed solution

Correct option is B

TVγ-1 = constant ⇒ T ∝ V1-γAccording to question T ∝ V-12Hence 1-γ = -12 ⇒ γ = 32= 1.5

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A gas expands adiabatically at constant pressure such that its temperature T ∝ 1V, the value of CpCv of gas is

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A gas expands adiabatically at constant pressure such that its temperature $T \propto \frac{1}{\sqrt{V}}$ , the value of $\frac{C_{p}}{C_{v}}$ of gas is