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Q.

A gas expands with temperature according to the relation V=KT1/3. What is the work done when the temperature changes by 30oC

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a

10R

b

20R

c

30R

d

40R

answer is A.

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Detailed Solution

V=KT1/3⇒dV=13KT−23dT⇒=13VT1/3T−23dT⇒dV=13V⋅T−1dT⇒dVV=13dTT⇒W=∫1/3T2 RTTdT=13RT2−T1⇒W=13×R×30=10R
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