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Questions  

A gas expands with temperature according to the relation V=KT1/3. What is the work done when the temperature changes by 30oC

a
10R
b
20R
c
30R
d
40R

detailed solution

Correct option is A

V=KT1/3⇒dV=13KT−23dT⇒=13VT1/3T−23dT⇒dV=13V⋅T−1dT⇒dVV=13dTT⇒W=∫1/3T2 RTTdT=13RT2−T1⇒W=13×R×30=10R

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