A gas expands with temperature according to the relation V=KT1/3. What is the work done when the temperature changes by 30oC

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10 R

20 R

30 R

40 R

answer is A.

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Detailed Solution

V=KT1/3⇒ dV=13 KT−23 dT⇒ =13 VT1/3 T−23 dT⇒ dV =13 V. T−1 dT⇒ dVV =13 dTT ⇒ W=∫T2T1 RTT dT=13 R T2−T1⇒ W=13 × R × 30=10R

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