A gas has   γ=4/3 and is heated at constant pressure, what percentage of total heat supplied is used for doing external work:

given specific heat ratio= γ=CpCv=43total heat supplied=∆Q=nCp∆Texternal work done = ∆W=nR∆Tpercentage of total heat supplied in doing external work =∆W∆Qx100 =nR∆TnCp∆Tx100 =RCpx100 =Cp-CvCpx100 =(1-1γ)100 =(1-143)100 =(1-34)100 =14x100 =25%