First slide
Thermodynamic processes
Question

A gas has molar heat capacity C=24.9 J/mol K in the process  P2T=Constant. Then (R=8.3 J/mol K
 

Moderate
Solution

Given
Molar heat capacity C=24.9 J/mol K

R=8.3J/molK As P2T= constant P2(PV)= constant P3V= constant PV1/3= constant (x=1/3)C=fR2+R1x24.9=f2+11x8.324.9=f2+111/38.3

24.98.3=f2+32f+3=6f=3

After solving we get  f=3
 So the gas is monoatomic 

 

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