A gas has molar heat capacity C=24.9 J/mol K in the process  P2T=Constant. Then (R=8.3 J/mol K)

GivenMolar heat capacity C=24.9 J/mol KR=8.3J/molK As P2T= constant ⇒P2(PV)= constant ⇒P3V= constant ⇒PV1/3= constant ⇒(x=1/3)C=fR2+R1−x⇒24.9=f2+11−x8.3⇒24.9=f2+11−1/38.3⇒24.98.3=f2+32⇒f+3=6∴f=3After solving we get  f=3⇒ So the gas is monoatomic