First slide

Law of equipartition of energy

Question

For a gas if ratio of specific heats at constant pressure and volume is $\large \gamma$ then value of degrees of freedom is

Easy

A

$\frac{{3\gamma - 1}}{{2\gamma - 1}}$
B

$\frac{2}{{\gamma - 1}}$
C

$\frac{9}{2}\left( {\gamma - 1} \right)$
D

$\frac{{25}}{2}\left( {\gamma - 1} \right)$

Solution

$\gamma \, = \,1 + \frac{2}{f};\,f\, = \,\frac{2}{{\gamma - 1}}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App