First slide

Heat ;work and internal energy

Question

A gas is taken through the cycle $A \to B \to C \to A$ as shown, what is the net work done

Moderate

A

1000 J
B

Zero
C

-2000 J
D

2000 J

Solution

$\begin{array}{rcl} work done is equal to area enclosed in the curve, it is a triangle \\ a r e a o f t r i a n g l e & = & \frac{1}{2} ×base×height \\ \Rightarrow & W= \frac{1}{2} ×AC×BC \\ \Rightarrow & W = \frac{1}{2} × [7 - 2] \times 10^{-3} \times (6 - 2) \times 10^{5} \\ \Rightarrow & W =10 \times 10^{2} \\ \Rightarrow & Work done=1000 J \end{array}$

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