A gas undergoes a change of state during which 100 J of heat is supplied to it and it does 20 J of work. The system is brought back to its original state through a process during which 20 J of heat is rejected by the gas. The work done (in J) by the gas in the second process is _______.
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answer is 60.
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Detailed Solution
Given that ΔQ1=100J ΔW1=20JΔQ2=−20JFor a cyclic process we use ΔQ1−ΔW1=−ΔQ2−ΔW2⇒ 100−20=−−20−ΔW2⇒ ΔW2=80−20=60J