Q.
A gas is undergoing an adiabatic process. At a certain stage A, the values of volume and temperature (V0, T0). From the details given in the graph, find the value of adiabatic constant γ
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a
V0T0tan θ+1
b
V0 tan θT0+1
c
V0 tan2θT0+1
d
V0T0+tan θ
answer is A.
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Detailed Solution
We have, for an adiabatic process, in relation with temperature and volumeTVγ-1 = constantDifferentiating with respect to T.Vγ-1.1 + T.(γ-1)Vγ-2dVdT = 0dVdT = VT(γ-1)But from the graph dVdT(T0,V0)= tan(π-θ) = -tan θV0T0(γ-1) = tan θ ⇒ γ-1 = V0T0tan θγ = V0T0tan θ+1
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