Questions
A gas is undergoing an adiabatic process. At a certain stage A, the values of volume and temperature . From the details given in the graph, find the value of adiabatic constant
detailed solution
Correct option is A
We have, for an adiabatic process, in relation with temperature and volumeTVγ-1 = constantDifferentiating with respect to T.Vγ-1.1 + T.(γ-1)Vγ-2dVdT = 0dVdT = VT(γ-1)But from the graph dVdT(T0,V0)= tan(π-θ) = -tan θV0T0(γ-1) = tan θ ⇒ γ-1 = V0T0tan θγ = V0T0tan θ+1Talk to our academic expert!
Similar Questions
During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of for the gas is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests