Download the app

Questions  

A gas is undergoing an adiabatic process. At a certain stage A, the values of volume and temperature (V0, T0). From the details given in the graph, find the value of adiabatic constant γ

a
V0T0tan θ+1
b
V0 tan θT0+1
c
V0 tan2θT0+1
d
V0T0+tan θ

detailed solution

Correct option is A

We have, for an adiabatic process, in relation with temperature and volumeTVγ-1 = constantDifferentiating with respect to T.Vγ-1.1 + T.(γ-1)Vγ-2dVdT = 0dVdT = VT(γ-1)But from the graph dVdT(T0,V0)= tan(π-θ) = -tan θV0T0(γ-1) = tan θ ⇒ γ-1 = V0T0tan θγ = V0T0tan θ+1

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its  temperature. The ratio of  CpCV  for the gas is  


phone icon
whats app icon