A gas with state (P, V, T) undergoes an adiabatic process in which its state become 833P,34V,x. Value of x is
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a
32T93
b
2T3
c
T32
d
3T2
answer is B.
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Detailed Solution
For adiabatic process,PVγ= constant ⇒P0V0γ=833P034V0γ…(i) Also, T1V1γ−1=T2V2γ−1⇒TV0γ−1=T234V0γ−1… (ii) Solving (i) for γ and keeping its value in (ii) we get,T2=2T3