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Q.

A gaseous mixture enclosed in a vessel consists of one gm mole of a gas A with (γ=5/3) and another B with (γ=7/5) at a temperature T. The gases A and B do not react with each other and assumed to be ideal. Find the number of gram moles of the gas B if γ of the gaseous mixture is 19/13.

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answer is 2.

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Detailed Solution

n1γ1−1+n2γ2−1=n1+n2γmix −1​ Here,  n1=1 and n2=?​γ1=5/3 and γ2=7/5​ Substituting these values in above equation, we get ​153−1+n275−1=1+n21913−1​ ⇒32+5n22=13(1+n2)6​⇒3(3+5n2)=13(1+n2)⇒​9+15n2=13+13n2​⇒n2=2
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A gaseous mixture enclosed in a vessel consists of one gm mole of a gas A with (γ=5/3) and another B with (γ=7/5) at a temperature T. The gases A and B do not react with each other and assumed to be ideal. Find the number of gram moles of the gas B if γ of the gaseous mixture is 19/13.