First slide

P-N junction diode

Question

Ge and Si diodes conduct at 0.3 V and 0.7 V, respectively. In the following figure, if Ge diode connection are reversed, the valve of $V_{0}$ changes by

Moderate

A

0.2 V
B

0.4 V
C

0.6 V
D

0.8 V

Solution

Consider the case when Ge and Si diodes are connected as shown in the given figure. Equivalent voltage drop across the combination G and Si diode = 0.3 V
$\Rightarrow Current i = \frac{12 - 0.3}{5 kΩ} = 2.34 mA$
$∴$ Output voltage, $V_{o} = Ri = 5 kΩ \times 2.34 mA = 11.7 V$
Now consider the case when Ge diode connection is reversed. In this case voltage drop across the diode's combination = 0.7 V
$\Rightarrow Current i = \frac{12 - 0.7}{5 kΩ} = 2.26 mA$
$∴ V_{o} - iR = 2.26 mA \times 5 kΩ = 11.3 V$
hence, change in the value of $V_{o} = 11.7 V - 11.3 = 0.4 V$

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