A Ge specimen is doped with Al. The concentration of acceptor atoms is 1021 atoms / m3 . Given that the intrinsic concentration of electron -hole pairs is 1019 / m3 , the concentration of electrons in the specimen is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1017 / m3
b
1015 / m3
c
104 /m3
d
102 / m3
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
When Ge specimen is doped with Al, then concentration of acceptor atoms is also called concentration of holes. Using formula, ni2=n0p0wheren1 = concentration of electron hole pair = 1019m-3n0 = concentration of electronp0 = concentration of holes = 1021atom m-3⇒10192=1021×n0⇒n0=1017m−3