To generate a power of 3.2megawatt, the number of fissions of U235 per minute is(Energy released per fission=200MeV, 1eV=1.6×10−19J )

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6×1018

6×1017

1017

6×1016

answer is A.

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Detailed Solution

3.2×106=n200×106×1.6×10−19n is no. per sec.n=3.2×1019200×1.6=1017Per minute - 60×1017=6×1018

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