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Questions

To generate a power of 3.2megawatt, the number of fissions of $U^{235}$ per minute is
(Energy released per fission=200MeV, 1eV= $1 .6 \times 10^{- 19} J$ )

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a

6×1018

b

6×1017

c

1017

d

6×1016

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detailed solution

Correct option is A

3.2×106=n200×106×1.6×10−19n is no. per sec.n=3.2×1019200×1.6=1017Per minute - 60×1017=6×1018

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Similar Questions

What is the total energy emitted for given fission reaction

$_{0}^{1} n +_{92}^{235} U ⟶_{92}^{236} U ⟶_{40}^{98} Z r +_{52}^{136} T e + 2_{0}^{1} n$

The daughter nuclei are unstable therefore they decay into stable end products ${}_{42}^{98}M o and {}_{54}^{136}X e$ by successive emission of β-particles. Let mass of $_{0}^{1} n = 1.0087$ amu, mass of $_{92}^{235} U = 236.0526$ amu, mass of $_{54}^{136} Xe = 135.9170$ amu, mass of ${}_{42}^{98}M o$ = 97.9054

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