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To generate a power of 3.2megawatt, the number of fissions of  U235 per minute is
(Energy released per fission=200MeV, 1eV=1.6×1019J )

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By Expert Faculty of Sri Chaitanya
a
6×1018
b
6×1017
c
1017
d
6×1016
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detailed solution

Correct option is A

3.2×106=n200×106×1.6×10−19n is no. per sec.n=3.2×1019200×1.6=1017Per minute -  60×1017=6×1018


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Similar Questions

What is the total energy emitted for given fission reaction

 01n+92235U92236U4098Zr+52136Te+201n

The daughter nuclei are unstable therefore they decay into stable end products M 4298o and X 54136e by successive emission of β-particles. Let mass of   01n=1.0087 amu, mass of  92235U=236.0526 amu, mass of  54136Xe=135.9170 amu, mass of M 4298o = 97.9054 

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