Questions
To generate a power of 3.2megawatt, the number of fissions of per minute is
(Energy released per fission=200MeV, 1eV= )
detailed solution
Correct option is A
3.2×106=n200×106×1.6×10−19n is no. per sec.n=3.2×1019200×1.6=1017Per minute - 60×1017=6×1018Similar Questions
What is the total energy emitted for given fission reaction
The daughter nuclei are unstable therefore they decay into stable end products by successive emission of β-particles. Let mass of amu, mass of amu, mass of amu, mass of = 97.9054
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