First slide

Energy released in nuclear reactions -Q-value

Question

To generate a power of 3.2megawatt, the number of fissions of $U^{235}$ per minute is
(Energy released per fission=200MeV, 1eV= $1 .6 \times 10^{- 19} J$ )

Moderate

A

$6 \times 10^{18}$
B

$6 \times 10^{17}$
C

$10^{17}$
D

$6 \times 10^{16}$

Solution

$3 .2 \times 10^{6} = n (200 \times 10^{6} \times 1 .6 \times 10^{- 19})$
n is no. per sec.
$n = \frac{3 .2 \times 10^{19}}{200 \times 1 .6} = 10^{17}$
Per minute - $60 \times 10^{17} = 6 \times 10^{18}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App