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Q.

A geostationary satellite orbits around the earth in a circular orbit of radius 36000 km. Then, the time period of a satellite orbiting a few hundred kilometres above the earth’s surface  (REarth=6400 km) will approximately be

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a

1/2 h

b

1 h

c

2 h

d

4 h

answer is C.

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T2T1=r2r13/2⇒T2=246400360003/2≅2 hour
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