First slide

Boolean operation

Question

To get an output 1 from the circuit shown in the figure, the input must be

Easy

A

$A = 0, B = 1, C = 0$
B

$A = 1, B = 0, C = 0$
C

$A = 1, B = 0, C = 1$
D

$A = 1, B = 1, C = 0$

Solution

The Boolean expression for the given combination is
output $Y = (A + B) \cdot C$
The truth table is
A B C Y=(A+B).C
0 0 0 0
1 0 0 0
0 1 0 0
0 0 1 0
1 1 0 0
0 1 1 1
1 0 1 1
1 1 1 1
$Hence A = 1, B = 0, C = 1$

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