First slide

Redistribution of charges and concept of common potential

Question

In the given arrangement of capacitors, $6 μC$ charge is added to point a. Find the charge on upper capacitor.

Moderate

A

$3 μC$
B

$1 μC$
C

$2 μC$
D

$6 μC$

Solution

$\frac{q_{1}}{1} = \frac{q_{2}}{2} = \frac{q_{3}}{3} = K$
$q_{1} + q_{2} + q_{3} = 6$
Solving, we get
K = 1
or $q_{3} = 3 μC$

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