First slide

Vectors

Question

Given that $\vec{A} + \vec{B} = \vec{C}$ and that $\vec{C}$ is perpendicular to $\vec{A}$ . Further if $| \vec{A} | = \vec{| C} |$ , then what is the angle between $\vec{A} and \vec{B}$ ?

Moderate

A

$\frac{π}{4} radian$
B

$\frac{π}{2} radian$
C

$\frac{3 π}{4} radian$
D

$π$ radian

Solution

A = C
$tanθ = \frac{C}{A} = 1$
$\Rightarrow θ = 45^{0} = \frac{π}{4}$
Angle between $\vec{A} and \vec{B}$
180- $θ = 180^{0} - 45 = 135^{0} = \frac{3 π}{4} rad$

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