Given that A→+B→=C→ and that C→ is perpendicular to A→. Further if |A→|=|C→|, then what is the angle between A→ and B→ ?
π4 radian
π2 radian
3π4 radian
π radian
A=Ctanθ=CA=1
⇒ θ=45∘=π4 Angle between A→ and B→ is 180−θ=180∘−45∘=135∘=3π4rad