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Given that A→+B→=C→ and that C→ is perpendicular to A→. Further if |A→|=|C→|, then what is the angle between A→ and B→ ?

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a

π4 radian

b

π2 radian

c

3π4 radian

d

π radian

answer is C.

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Detailed Solution

A=Ctan⁡θ=CA=1⇒ θ=45∘=π4 Angle between A→ and B→ is 180−θ=180∘−45∘=135∘=3π4rad

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