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Q.

Given that A→+B→=C→. If |A→|=4,|B→|=5 and |C→|=61 the angle between A→ and B→ is

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a

30o

b

60o

c

90o

d

120o

answer is B.

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Detailed Solution

A→+B→=C→ (A→+B→)⋅(A→+B→)=C→⋅C→⇒ A2+B2+2ABcos⁡θ=C2 42+52+2×4×5cos⁡θ=61⇒ cos⁡θ=12⇒θ=60∘

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