Given that A→+B→+C→=0 out of three vectors two are equal in magnitude and the magnitude of third vector is 2 times that of either of the two having equal magnitude. Then the angles between vectors are given by
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a
30∘,60∘,90∘
b
45∘,45∘,90∘
c
45∘,60∘,90∘
d
90∘,135∘,135∘
answer is D.
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Detailed Solution
From polygon law, three vectors having summation zero should form a closed polygon (Triangle). Since the two vectors are having same magnitude and the third vector is 2 times that of either of two having equal magnitude. That is, the triangle should be right angled triangle.Angle between A and B, α=90∘Angle between B and C, β=135∘Angle between A and C, γ=135∘
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Given that A→+B→+C→=0 out of three vectors two are equal in magnitude and the magnitude of third vector is 2 times that of either of the two having equal magnitude. Then the angles between vectors are given by