First slide

Vectors

Question

Given that A+B=R and A-B=R. The angle between A and B is

Easy

A

0
B

$π / 4$
C

$π / 2$
D

$π$

Solution

$\sqrt{A^{2} + B^{2} + 2 A B C O S θ} = \sqrt{A^{2} + B^{2} - 2 A B C O S θ}$
COS $θ$ = 0
THEN $θ = π / 2$

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