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Q.

A given charge is situated at a certain distance from an electric dipole in the end-on position, experiences a force F. If the distance of the charge is doubled, the force acting on the charge will be

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a

2F

b

F/2

c

F/4

d

F/8

answer is D.

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Detailed Solution

We know that for end-on position Eend on =14πε0×2pr3∴ F=14πε0×2pqr3When the distance is doubled, thenF′=14πε0×2pq(2r)3=1814πε0×2pqr3=F8

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