In the given circuit, the current I₁ is

detailed solution

Correct option is B

The circuit can be simplified as follows:Applying KCL at junction A⇒    I3= I1+I2                              .....iApplying Kirchhoff's voltage law for the loop ABCDA,−30I1−40I3+40=0                 ⇒    −30I1−40I1  +  I2+40=0   ⇒    7I1+4I2=4                              .....iiApplying Kirchhoff's voltage law for the loop ADEFA,−40I1−40I3+80+40=0                 ⇒    −40I2−40I1  +  I2=−120   ⇒    I1+2I2=3                              .....iiiOn solving equations (ii) and (iii), I1=−0.44  A