First slide

Diodes

Question

In the given circuit, the current through the battery is

Moderate

A

0.5A
B

1A
C

1.5A
D

2A

Solution

$D_{1}$ is in reverse bias( no current flows through that branch) and $D_{2}, D_{3}$ are in forward bias (behaves like conducting wire)
$R_{e q} = \frac{20 \times 20}{20 + 20} = 10 Ω$
Ohm's Law : $i = \frac{5}{10} = 0.5 A$

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