In the given circuit diagram, E=12V, C1=4μF, C2=2μF, C3=6μF and C4=3μF. Find the heat produced in the circuit (in μJ) after switch S is shorted.

With S openNet emf = 0∴ Charge on all capacitors = 0With S closed Energy stored in capacitorsU=q122C1+q122C2+q222C3+q222C4=240 μJWork done by cells = 480 μJHeat produced = 240 μJ