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Q.

In the given circuit diagram, E=12V, C1=4μF, C2=2μF, C3=6μF and C4=3μF. Find the heat produced in the circuit (in μJ) after switch S is shorted.

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answer is 240.

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Detailed Solution

With S openNet emf = 0∴ Charge on all capacitors = 0With S closed Energy stored in capacitorsU=q122C1+q122C2+q222C3+q222C4=240 μJWork done by cells = 480 μJHeat produced = 240 μJ
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