In the given circuit diagram, initially the switch S is opened. Find heat dissipated in the circuit (in$$ $$mJ) after switch S in closed. It is given $$C=2$$μF.

Question

In the given circuit diagram, initially the switch S is opened. Find heat dissipated in the circuit (in$$ $$mJ) after switch S in closed. It is given $$C=2$$μF.

Infinity Learn · Accepted Answer

When switch S is opened the potential difference across the group of capacitors is zero. Hence the initial charge in both the capacitors will be zero.

When the switch S is closed, potential difference across both of them is 30 V. Charge on each of them is $q = (2 μF) (30 V) = 60 μC$

The heat developed in the circuit $H = E n e r g y r e l e a s e d b y 60 V b a t t e r y - (E n e r g y a b s o r b e d b y b o t h 30 V b a t t e r y + E n e r g y s t o r e d i n b o t h c a p a c i t o r s)$

$= 1800 μJ = 1 .8 mJ$

Capacitors and capacitance

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In the given circuit diagram, initially the switch S is opened. Find heat dissipated in the circuit (in mJ) after switch S in closed. It is given $C = 2 μF$ .

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Capacitors and capacitance

Remember concepts with our Masterclasses.

In the given circuit diagram, initially the switch S is opened. Find heat dissipated in the circuit (in mJ) after switch S in closed. It is given C=2μF.

Ready to Test Your Skills?

free study material

In the given circuit diagram, initially the switch S is opened. Find heat dissipated in the circuit (in mJ) after switch S in closed. It is given $C = 2 μF$ .