In the given circuit [fig]potential difference across the capacitor must be

In steady state no current will pass through the capacitor. The current flowing in the circuit is shown in figFrom figi=2V−VR+2R=V3RVC−VA=iR+V=V3+V=4V3Further, VC−VA=VC−VB+VB−VA∴ VC−VB=VC−VA−VB−VA=4V3−V=V3So, the potential drop across the capacitor will be V / 3.