First slide

Diodes

Question

The given circuit has two ideal diodes connected as shown in the figure below. The Current flowing through the resistance $R_{1}$ will be

Moderate

A

2.5A
B

10 A
C

1.43 A
D

3.13 A

Solution

Diode $D_{1}$ is in Reverse bias (no current through this branch)
Diode $D_{2}$ is in forward bias (behaves like conducting wire)
$ε_{n e t} = 10 v R_{n e t} = R_{1} + R_{3} = 2 + 2 = 4 i_{n e t} = \frac{E_{n e t}}{R_{n e t}} = \frac{10}{4} = 2.5 A$
Current flowing through resistance $R_{1}$ is 2.5 A

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