In the given circuit, it is observed that the current I is independent of the value of the resistance R6. Then the resistance values must satisfy
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a
R1R2R5= R3R4R6
b
1R5+1R6= 1R1+ R2+1R3 + R4
c
R1R4= R2R3
d
R1R3= R2R4= R5R6
answer is C.
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Detailed Solution
As I is independent of R6, no current flows through R6. This requires that the junction of R1 and R2 is at the same potential as the junction of R3 and R4. This must satisfy the condition R1R2=R3R4, as in the Wheatstone bridge.