First slide

Capacitance

Question

In the given circuit, a potential difference of 60 V is applied across AB. The potential difference between points M and N is:

Moderate

A

10 V
B

15 V
C

20 V
D

30 V

Solution

$V = V_{1} + V_{2} + V_{3} = 60 60 = \frac{Q}{2 C} + \frac{Q}{C} + \frac{Q}{2 C} ∴ \frac{2 Q}{C} = 60, \frac{Q}{C} = 30 V = P.D. across MN$

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