A given equiconvex lens is cut into four parts and the parts are rearranged as shown. If the initial focal length is f, then after rearrangement the equivalent focal length is
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a
f
b
f2
c
f4
d
4f
answer is B.
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Detailed Solution
Cutting a lens in transverse direction doubles their focal length i.e. 2f.using the formula of equivalent focal length 1F=1f1+1f2+1f3+1f4=42f=2f⇒F=f2