The given fig. shows two identical parallel plate capacitors connected to a battery with switch S is closed. The switch is now opened and free space between the plates of the capacitors is now filled with dielectric of K = 3. Then, ratio of energy stored in both capacitors before and after introduction of dielectric is ;

Question

Infinity Learn · Accepted Answer

As switch S is closed; $$VA=VB=V$$ ∴     $$Ei=12CV2+12CV2=CV2After$$ introduction of slab as switch S is now opened, $$VA=V$$ and $$CA=3C$$&$$CB=3C$$ and Let VB′$$=new$$ pot. difference across capacitor B. Acc. to law of conservation of charge in case of capacitor B;$$CV=3CVB$$′⇒ VB′$$=V3$$∴ $$Ef=12CAV2+12CBVB2=53CV2$$

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